Pressure, Volume, Quantity, and Temperature - Revision history

Microft: /* Extra Credit!! */

2022-06-07T20:05:09Z

Extra Credit!!

← Older revision		Revision as of 20:05, 7 June 2022
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	'''P = (nRT)/V'''<br>		'''P = (nRT)/V'''<br>
	'''dP/dn = (d/dn)(nRT)/V = (RT/V)*(dn/d)n = RT/V''' (in unites of Pascals per mole)		'''dP/dn = (d/dn)(nRT)/V = (RT/V)*(d/dn)n = RT/V''' (in unites of Pascals per mole)

	Change in temperature with respect to the change in pressure:		Change in temperature with respect to the change in pressure:
	'''T = (PV)/(nR)'''<br>		'''T = (PV)/(nR)'''<br>
	'''dT/dP = (d/dP){(PV)/(nR)} = {V/(nR)} * (d/dP)P = V/(nR)'''		'''dT/dP = (d/dP){(PV)/(nR)} = {V/(nR)} * (d/dP)P = V/(nR)'''

45.248.77.206: /* Definitions */

2021-09-17T01:46:55Z

Definitions

← Older revision		Revision as of 01:46, 17 September 2021
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	'''Quantity''': The number of particles contained in a particular space. In our case, it is the number of molecules measured in '''mol'''es. 1 Mole = 6.022E23 molecules. (or around 602,200,000,000,000,000,000,000 molecules. ).		'''Quantity''': The number of particles contained in a particular space. In our case, it is the number of molecules measured in '''mol'''es. 1 Mole = 6.022E23 molecules. (or around 602,200,000,000,000,000,000,000 molecules. ).

	'''Temperature''': A measure of the thermal energy of the gas. Once measured in Fahrenheit (in the dark times), now measured in degrees Celsius or Kelvin. To convert from Celsius to Kelvin, simply ~~subtract~~ 273.15. It is impossible to have a negative value on the Kelvin scale.		'''Temperature''': A measure of the thermal energy of the gas. Once measured in Fahrenheit (in the dark times), now measured in degrees Celsius or Kelvin. To convert from Celsius to Kelvin, simply add 273.15. It is impossible to have a negative value on the Kelvin scale.

	== Relating them all together ==		== Relating them all together ==

62.245.76.101: game limits on real world physics

2021-07-18T22:24:20Z

game limits on real world physics

← Older revision		Revision as of 22:24, 18 July 2021
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	== Relating them all together ==		== Relating them all together ==

	All four of the above values balance each other in any given system. A change in one will effect the others.		All four of the above values balance each other in any given system. A change in one will effect the others. But that applies only in real world. In this game there are some limits:
			* Only things that have atmosphere have temperature.
			* Anything facing vacuum will lose heat unless it is insulated.
			* Anything facing sunlight will gain heat.
			* All finished walls and finished cube frames are perfect insulators. Windows allow radiation from sun.
			* Like real world, increasing temperature will increase pressure. Lowering temperature will lower pressure.
			* Unlike real world, raising pressure will not raise temperature. Lowering pressure will not lower temperature. This prevents making own heat transfer designs using only pressure.

	=== For example===		=== For example===

93.133.147.191: /* Volume Pump Example */

2021-03-31T22:24:50Z

Volume Pump Example

← Older revision		Revision as of 22:24, 31 March 2021
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	== Volume Pump Example==		== Volume Pump Example==
	[[File:FurnaceAndPipes.png\|thumb]]		[[File:FurnaceAndPipes.png\|thumb]]
	Using the same conditions as above, assume there is a volume pump attached to the input (like you find on an advanced furnace. If you're poor and can't afford an advanced furnace, use a regular furnace with an attached volume pump on the inlet. You hobo). Assume the pressure behind the volume pump is at a steady 50 Megapascals (50E6 Pascals) at 200 ~~degrees~~ Kelvin and there is 5 pipe segments (100 Liters per pipe segment = 500 Liters). The stationer (being dumb, I guess) turns the pump up to 100 Liters. How much pressure is going to be added to the system on each game tick? Should the stationeer be sh***ing their space suit?		Using the same conditions as above, assume there is a volume pump attached to the input (like you find on an advanced furnace. If you're poor and can't afford an advanced furnace, use a regular furnace with an attached volume pump on the inlet. You hobo). Assume the pressure behind the volume pump is at a steady 50 Megapascals (50E6 Pascals) at 200 Kelvin and there is 5 pipe segments (100 Liters per pipe segment = 500 Liters). The stationer (being dumb, I guess) turns the pump up to 100 Liters. How much pressure is going to be added to the system on each game tick? Should the stationeer be sh***ing their space suit?

	''Now is a good time to mention that the dial on a volume pump is actually a measure of rate, not volume. When setting the volume pump to 10 Liters, it actually means "10 Liters per game tick". WHY it's just labelled as volume and what determines a game tick? I don't know, go ask the devloper - I'm busy.''		''Now is a good time to mention that the dial on a volume pump is actually a measure of rate, not volume. When setting the volume pump to 10 Liters, it actually means "10 Liters per game tick". WHY it's just labelled as volume and what determines a game tick? I don't know, go ask the devloper - I'm busy.''
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	* n = (PV)/(RT)		* n = (PV)/(RT)
	* R = 8314.46 (This is always the same.. That's why they call it a 'constant)		* R = 8314.46 (This is always the same.. That's why they call it a 'constant)
	* T = 200 ~~degrees~~ Kelvin		* T = 200 Kelvin
	* P = 50E6 Pascals		* P = 50E6 Pascals
	* V = 500 Liters of pipe (5 segments, each holding 100 Liters)		* V = 500 Liters of pipe (5 segments, each holding 100 Liters)

93.133.147.191: /* Definitions */

2021-03-31T22:22:03Z

Definitions

← Older revision		Revision as of 22:22, 31 March 2021
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	'''Quantity''': The number of particles contained in a particular space. In our case, it is the number of molecules measured in '''mol'''es. 1 Mole = 6.022E23 molecules. (or around 602,200,000,000,000,000,000,000 molecules. ).		'''Quantity''': The number of particles contained in a particular space. In our case, it is the number of molecules measured in '''mol'''es. 1 Mole = 6.022E23 molecules. (or around 602,200,000,000,000,000,000,000 molecules. ).

	'''Temperature''': A measure of the thermal energy of the gas. Once measured in Fahrenheit (in the dark times), now measured in degrees Celsius or ~~degrees~~ Kelvin. To convert from Celsius to Kelvin, simply subtract 273.15 ~~degrees~~. It is impossible to have a negative value on the Kelvin scale.		'''Temperature''': A measure of the thermal energy of the gas. Once measured in Fahrenheit (in the dark times), now measured in degrees Celsius or Kelvin. To convert from Celsius to Kelvin, simply subtract 273.15. It is impossible to have a negative value on the Kelvin scale.

	== Relating them all together ==		== Relating them all together ==

Microft at 18:17, 21 January 2021

2021-01-21T18:17:44Z

← Older revision		Revision as of 18:17, 21 January 2021
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	''Side note: I use engineering notation here sometimes. For example, one thousand can be shown as 1E3. I may also use a 'k' too, but that can sometimes be confused with the K for Kelvins, so I try to stay clear of it.''		''Side note: I use engineering notation here sometimes. For example, one thousand can be shown as 1E3. I may also use a 'k' too, but that can sometimes be confused with the K for Kelvins, so I try to stay clear of it.''

	''Side side note: ~~I haven't checked these~~ calculations.''		''Side side note: These calculations are greatly simplified and account for one variable change at a time.''

	== Definitions==		== Definitions==

Microft at 18:08, 21 January 2021

2021-01-21T18:08:51Z

← Older revision		Revision as of 18:08, 21 January 2021
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	* T - Temperature in Kelvin		* T - Temperature in Kelvin
	* R - Ideal Gas Constant (in this case, we use 8314.46261815324) in unites of (deep breath..) Liter Pascals per Kelvin moles (Lit * Pa)/(mol * deg K)		* R - Ideal Gas Constant (in this case, we use 8314.46261815324) in unites of (deep breath..) Liter Pascals per Kelvin moles (Lit * Pa)/(mol * deg K)

			[[File:Furnace2.png\|thumb]]

	So, if we had a furnace with 2 mol of gas in it at 300 degrees Kelvin, what would be the pressure? (A furnace has a 1,000 liter capacity)		So, if we had a furnace with 2 mol of gas in it at 300 degrees Kelvin, what would be the pressure? (A furnace has a 1,000 liter capacity)
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	== Volume Pump Example==		== Volume Pump Example==
			[[File:FurnaceAndPipes.png\|thumb]]
	Using the same conditions as above, assume there is a volume pump attached to the input (like you find on an advanced furnace. If you're poor and can't afford an advanced furnace, use a regular furnace with an attached volume pump on the inlet. You hobo). Assume the pressure behind the volume pump is at a steady 50 Megapascals (50E6 Pascals) at 200 degrees Kelvin and there is 5 pipe segments (100 Liters per pipe segment = 500 Liters). The stationer (being dumb, I guess) turns the pump up to 100 Liters. How much pressure is going to be added to the system on each game tick? Should the stationeer be sh***ing their space suit?		Using the same conditions as above, assume there is a volume pump attached to the input (like you find on an advanced furnace. If you're poor and can't afford an advanced furnace, use a regular furnace with an attached volume pump on the inlet. You hobo). Assume the pressure behind the volume pump is at a steady 50 Megapascals (50E6 Pascals) at 200 degrees Kelvin and there is 5 pipe segments (100 Liters per pipe segment = 500 Liters). The stationer (being dumb, I guess) turns the pump up to 100 Liters. How much pressure is going to be added to the system on each game tick? Should the stationeer be sh***ing their space suit?

Microft: A quick tutorial on how temperature, pressure, volume, and quantity are calculated. Also contains some examples on calculating furnace behavior.

2021-01-21T17:54:45Z

A quick tutorial on how temperature, pressure, volume, and quantity are calculated. Also contains some examples on calculating furnace behavior.

← Older revision		Revision as of 17:54, 21 January 2021
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	So, if we had a furnace with 2 mol of gas in it at 300 degrees Kelvin, what would be the pressure? (A furnace has a 1,000 liter capacity)		So, if we had a furnace with 2 mol of gas in it at 300 degrees Kelvin, what would be the pressure? (A furnace has a 1,000 liter capacity)

	~~'''PV = nRT'''~~		Rearrange for Pressure:

	~~Rearrange for Pressure:<br>~~		'''P = (nRT)/V'''<br>
	'''P=(nRT)/V<br>		'''P = (2 * 8314.46 * 300)/1000 = (approx) 5 kPa (or 5000 Pascals)'''
	P = (2 * 8314.46 * 300)/1000 = (approx) 5 kPa (or 5000 Pascals)'''

	Similarly, you can rearrange this equation to solve for volume, temperature, and quantity as needed.		Similarly, you can rearrange this equation to solve for volume, temperature, and quantity as needed.
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	== Volume Pump Example==		== Volume Pump Example==

	Using the same conditions as above, assume there is a volume pump attached to the input (like you find on an advanced furnace. If you're poor and can't afford an advanced furnace, use a regular furnace with an attached volume pump on the inlet. You hobo). Assume the pressure behind the volume pump is at a steady 50 Megapascals (50E6 Pascals) at 200 degrees Kelvin and there is 5 pipe segments (100 Liters per pipe segment = 500 Liters). ~~That~~ stationer (being dumb, I guess) turns the pump up to 100 Liters. How much pressure is going to be added to the system on each game tick? Should the stationeer be sh***ing their space suit?		Using the same conditions as above, assume there is a volume pump attached to the input (like you find on an advanced furnace. If you're poor and can't afford an advanced furnace, use a regular furnace with an attached volume pump on the inlet. You hobo). Assume the pressure behind the volume pump is at a steady 50 Megapascals (50E6 Pascals) at 200 degrees Kelvin and there is 5 pipe segments (100 Liters per pipe segment = 500 Liters). The stationer (being dumb, I guess) turns the pump up to 100 Liters. How much pressure is going to be added to the system on each game tick? Should the stationeer be sh***ing their space suit?

	''Now is a good time to mention that the dial on a volume pump is actually a measure of rate, not volume. When setting the volume pump to 10 Liters, it actually means "10 Liters per game tick". WHY it's just labelled as volume and what determines a game tick? I don't know, go ask the devloper - I'm busy.		''Now is a good time to mention that the dial on a volume pump is actually a measure of rate, not volume. When setting the volume pump to 10 Liters, it actually means "10 Liters per game tick". WHY it's just labelled as volume and what determines a game tick? I don't know, go ask the devloper - I'm busy.''
	''
	First thing you need to figure out is now many moles of gas ~~their are per liter~~ in the pipe. So, rearrange the magical equation for n:		First thing you need to figure out is now many moles of gas is in the pipe per liter. So, rearrange the magical equation for n:
	n = (PV)/(RT)
	R = 8314.46 (This is always the same.. That's why they call it a 'constant)		* n = (PV)/(RT)
	T = 200 degrees Kelvin		* R = 8314.46 (This is always the same.. That's why they call it a 'constant)
	P = 50E6 Pascals		* T = 200 degrees Kelvin
	V = 500 Liters of pipe (5 segments, each holding 100 Liters)		* P = 50E6 Pascals
			* V = 500 Liters of pipe (5 segments, each holding 100 Liters)

	You can also calculate the number of moles in the pipe and divide that by the volume of the pipe (each pipe segment is 100 Liters):		You can also calculate the number of moles in the pipe and divide that by the volume of the pipe (each pipe segment is 100 Liters):
	n = (PV)/(RT) = (5E6 * 500)/(8314.46 * 200) = 1503.4 moles of gas in the pipe.
			'''n = (PV)/(RT) = (5E6 * 500)/(8314.46 * 200) = 1503.4''' moles of gas in the pipe.

	1503.4 moles of gas contained in 500 Liters of pipe means each liter has 1503.4/500 = approximately 3 moles of gas per Liter.		1503.4 moles of gas contained in 500 Liters of pipe means each liter has 1503.4/500 = approximately 3 moles of gas per Liter.
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	How much pressure does 300 moles exert in the furnace? Arrange the equation to solve for pressure:		How much pressure does 300 moles exert in the furnace? Arrange the equation to solve for pressure:

	P = (nRT)/V		'''P = (nRT)/V'''

	Where:		Where:
	n = 300 moles		* n = 300 moles
	R = 8314.46 blah blah constant blah blah		* R = 8314.46 blah blah constant blah blah
	T = 300 degrees kelvin (remember, the furnace was a bit warmer than the pipes..)		* T = 300 degrees kelvin (remember, the furnace was a bit warmer than the pipes..)
	V = 1000 Liters (the volume of the furnace). "Go throw a log in the ten piper", grandpa would say..		* V = 1000 Liters (the volume of the furnace). "Go throw a log in the ten piper", grandpa would say..

	P=(nRT)/V = (3008314.46300)/1000 = 748301 Pascals (or 748 kPa).		'''P = (nRT)/V = (3008314.46300)/1000 = 748301 Pascals (or 748 kPa)'''.

	So, each game tick will add 748 kPa to the furnace at this rate. That's pretty quick. Not space suit soiling quick, but it can get out of hand if you're not careful. The furnace will blow around 60 MPa (I think) so....		So, each game tick will add 748 kPa to the furnace at this rate. That's pretty quick. Not space suit soiling quick, but it can get out of hand if you're not careful. The furnace will blow around 60 MPa (I think) so....
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	For those of you that are really keen, you can use calculus to compute rates. Assuming everything else remains constant, just differentiate the equation according the variables you need. So, if you want to know what the rate of change for pressure with respect to quantity (moles) you can:		For those of you that are really keen, you can use calculus to compute rates. Assuming everything else remains constant, just differentiate the equation according the variables you need. So, if you want to know what the rate of change for pressure with respect to quantity (moles) you can:

	P = (nRT)/V		'''P = (nRT)/V'''<br>
	dP/dn = (d/dn)(nRT)/V = (RT/V)*(dn/d)n = RT/V (in unites of Pascals per mole)		'''dP/dn = (d/dn)(nRT)/V = (RT/V)*(dn/d)n = RT/V''' (in unites of Pascals per mole)

	Change in temperature with respect to the change in pressure:		Change in temperature with respect to the change in pressure:
			'''T = (PV)/(nR)'''<br>
	T = (PV)/(nR)		'''dT/dP = (d/dP){(PV)/(nR)} = {V/(nR)} * (d/dP)P = V/(nR)'''
	dT/dP = (d/dP){(PV)/(nR)} = {V/(nR)} * (d/dP)P = V/(nR)

Microft: /* For example */

2021-01-21T17:44:42Z

For example

← Older revision		Revision as of 17:44, 21 January 2021
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	'''PV = nRT'''		'''PV = nRT'''

	Rearrange for Pressure:		Rearrange for Pressure:<br>
	'''P=(nRT)/V<br>		'''P=(nRT)/V<br>
	P = (2 * 8314.46 * 300)/1000 = (approx) 5 kPa (or 5000 Pascals)'''		P = (2 * 8314.46 * 300)/1000 = (approx) 5 kPa (or 5000 Pascals)'''

Microft: /* For example */

2021-01-21T17:44:26Z

For example

← Older revision		Revision as of 17:44, 21 January 2021
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	So how exactly do all these values play with each other? The answer to this question lies in the ideal gas equation:		So how exactly do all these values play with each other? The answer to this question lies in the ideal gas equation:

	P * V = n * R * T		'''P * V = n * R * T'''

	Where:		Where:

	P - Pressure in Pascals		* P - Pressure in Pascals
			* V - Volume in Liters
	V - Volume in Liters		* n - Quantity in moles
			* T - Temperature in Kelvin
	n - Quantity in moles		* R - Ideal Gas Constant (in this case, we use 8314.46261815324) in unites of (deep breath..) Liter Pascals per Kelvin moles (Lit * Pa)/(mol * deg K)

	T - Temperature in Kelvin

	R - Ideal Gas Constant (in this case, we use 8314.46261815324) in unites of (deep breath..) Liter Pascals per Kelvin moles (Lit * Pa)/(mol * deg K)

	So, if we had a furnace with 2 mol of gas in it at 300 degrees Kelvin, what would be the pressure? (A furnace has a 1,000 liter capacity)		So, if we had a furnace with 2 mol of gas in it at 300 degrees Kelvin, what would be the pressure? (A furnace has a 1,000 liter capacity)

	PV = nRT		'''PV = nRT'''

	Rearrange for Pressure:		Rearrange for Pressure:
	P=(nRT)/V		'''P=(nRT)/V<br>
	P = (2 * 8314.46 * 300)/1000 = (approx) 5 kPa (or 5000 Pascals)		P = (2 * 8314.46 * 300)/1000 = (approx) 5 kPa (or 5000 Pascals)'''

	Similarly, you can rearrange this equation to solve for volume, temperature, and quantity as needed.		Similarly, you can rearrange this equation to solve for volume, temperature, and quantity as needed.